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英語 高校生

解答教えて頂きたいです🙇‍♂️

2 LESSON 11 (3) Choose the underlined pers ple say that Janan i Chiagur) trong 1 Choose the best answer to fill in the blanks. (81) (1) I was ( Dabout to (2) Hiroshi's undergone the medical examination already, ( Disn't he (6) ( t to ista (4) She was so stubborn that she ( Dhad him th 2 will have ) leave the room when my cell phone rang. 2 going (3) There are few places downtown for parking, ( 1 at which 2 in which 3 where 1 Can (5) The man is a responsible and capable employee Das well as 2 better than 17 3 much better than 4 superior to (7) We help one ( 1 either (8) There is ( 1 no told 4 no telling (11) If I ( (1) am (13) ( 2 doesn't he Jan Ob 1 So as 4 yet 3 soon after innen )? (9) We do not necessarily grow wiser ( 1 as 2 than (10) The World Cup is held ( 1 all 2 every ) what will happen 2 not to tell 5 not having told hasn't he hasn't ) you, ) it be true that 70% of Americans believe in angels? 2 Must 3 Does 4 May ) never change her mind. 3 would did with the extra work in the summer. 2 another 3 two tomorrow. 3 not telling 3 more than ) four years. 3 each (12) Tom didn't hear the doorbell, because he ( has been taking 3 took 4 didn't helautoqqo) ) we grow older. I would call the police immediately. 2 had been (3) were is really a problem. 4 which 2 was taking has taken ) a delightful person to work w 4 both 4 so that 4 whole temper ) a bath. ) to dense fog, most of the flights will be delayed. 2 Due 3 Because 4 would be 4 Owe (中容 (日本歯 XAC (東北学 OS THE (西南学 FUMB 10 (広島経 (注 (芝浦] (京都造 G (3

解決済み 回答数: 1
数学 中学生

④と⑤とGが出てくる意味がわかりません。

右の図のように,関数y=ax²...アのグラフ上に3点 A, B, C, y 軸上に点Dを,四角形ABCDが平行四辺 形となるようにとり, 四角形ABCDの辺ABとy軸との 交点をEとする。 点Aの座標が(-4, -4), 点Bの座 標 (2, p) とする。 x軸上に点Fをとり, CDF の面 積と△AEDの面積が等しくなるとき, 点Fの座標を求め なさい。 ただし, 点F は, 直線 CD について, 原点と同 Å じ側にとるものとする。 <三重県 〉 解き方 2 求める座標を文字でおく 点Fの座標を文字でおき, 等式をつくって点Fの座標を求める。 y=1/x-2 解き方 3 必要な長さや、 座標, 直線などを求める △AED = - =1/12/2x - × 10×4=20 点のx座標とすると, F(f, 0) 直線DFは傾きが ④[ 点Cからy軸にひいた垂線と直線DFとの交点をGとすると, f G ( [ 4 A A なので.y=2x-12 y 0 PF 解き方 1 問題の条件を図に書き込む A(-4,-4) がy=ax2のグラフ上にあることより,アの式はy=①[ 〕 B(2.p) はy=-2x2のグラフ上にあるので、p=-12×22=-1 B(2,-1) 点Dのy座標をdとすると D (0, d) 四角形ABCD は平行四辺形なので,C② [ ), d+3) C(6.d+3) はy=-1 =-212x2のグラフ上にあるので.d+3=-2x62 d=-12 よって, C (6, -9), D (0, -12) 直線ABはA(-4, -4),B(2,-1)を通るので,y= よって, E(0, ③ [ D) D E -4 2 B 〕, -9) よってCG=6 △CDF=CDG+△CFG=12x16-1/4)×3+1/12x16-1/4)×9=616-1/4) CD=△AEDより 616-1)=20 これを解いて.J=⑨[ 答え DASI [1] x ]

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