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数学 高校生

20の(1)の角BACを求めるところで質問です 解答とはちょっと違くて β-α/γ-α=√2/2(cos5/4π+isin5/4π)となったのですが極形式のθ回転は右回りを指しているのでこのようになりますか? そういうことなら問題を解く時、点の位置をある程度把握する必要... 続きを読む

58 基本例題 30 線分のなす角、平行・垂直条件 複素数平面上の3点A(α), B(B), C(y) について (1) α=1+2i,β=-2+4i, y=2-ai とする。 このとき, 次のものを (ア) a=3のとき, ∠BAC の大きさと △ABCの面積 (イ) α=16のとき, CBA の大きさ (2) α=-1-i, β=i, y=b-2i (b は実数の定数) とする。 (ア) 3 点A,B,Cが一直線上にあるように, bの値を定めよ。 (イ)2 直線 AB, AC が垂直であるように, 6の値を定めよ。 指針 ∠BACの偏角 Bay = arg B-α Y-α (1)(ア) (1) B-a (ア) △ABCの面積は 1/12AB・ACsin <BAC また であるから, a-B Y-B = r-a β-a r-a に注目する。 = を計算し、 極形式で表す。 (2) pp.41 の基本事項 ③ ② ③ が適用できるように,まずy-a B-a r-a が実数 (∠BAC = 0 または ² ) B-α 解答 (1) (ア) α=3のとき, y=2-3i であるから Y-α 2-3i-(1+2i) B-a -2+4i-(1+2i) よって, ∠BACの大きさは r-a が純虚数 ∠BAC= B-a BAC=4) の計算で出てくる B-α, r-αの値を使うとよい。 (1-5i)(-3-2i) (-3+2i)(-3-2i) = √2 (cos+isin) CHART 線分のなす角、直線の平行・垂直偏角 ∠Bay=arg- 1-5i -3+2i =-1+i 3 △ABC=12AB・ACsin <BAC -—-—- √ √(-3)² + 2² ₁/18 11 12 B(B) p.41 3 0 A(a) ここで, AB=B-al, AC ∠Bay A(a) C(y) を計算し Big r-a B-a a-B r-B a=16 のとき, -ba 分母の実数化。 偏角を調べる。 = よって, ∠CBA y-a (b-2i)- B-a as litte i-(- (b+1-i (1+2i) 3点A, B, C となることであ よって イ) 2直線AB, 検討 ベクトルの となるように,bの値を定復素数平面上の点 いて解くこともで 1) (1) A(1, 2), B. 1+2i-( 2-16i-C = ここでは,偏角 (3-2i)(- 4(1-5i)0 習 00 √ 8 COS- 数となることで b= よって b=- CO (ア)についても 2) A(-1, -1) (ア)kを実数 よって (イ) AB・AC= 0≤ZCBAS 複素数平 (1)a= (2) α= 求め

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英語 高校生

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