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英語 高校生

教えてほしいです

2 次の英文を読み, 空所に入れるのに最も適切なものを,それぞれ下の①~④のうちから一つずつ選びなさい。 (6) When growing tomatoes, we know we should pick them when they're bright red. With carrots, however, ( 6 ) because they grow underground. ①we should pick them when they turn orange (2) it's hard to know when they're ready (3) we should grow them more carefully than tomatoes (4) it's easy to know when they're bright red (7) Although it is quick, easy and convenient to be able to look up information on the internet, it can sometimes be difficult ( 7 ) because there is so much information. to find what you are looking for (2) to improve the convenience of the internet (3) to get more than what you need that people often experie (4) to have good computer literacy (8) Would you be happier if you were richer? Many people believe that they would be. But research conducted over many years suggests that ( 8 ). People in the United States, for example, are, on average, richer than New Zealanders, but they are not happier. poorer people tend to worry about their financial problems 2 pleasure in life usually comes from great wealth (3) the best way to be happy is learning how to save money greater wealth doesn't generally imply greater happiness (9) Many European rivers were once heavily polluted by manufacturing industries. As a result, wild animals dependent on clean water disappeared. However, as stricter environmental standards took effect, rivers such as the Thames of London have become much cleaner. Consequently, ( 9 ). water quality has continued to decline wild animals avoid drinking from the Thames (3) wild animals are making a comeback in many rivers (4) wild animals no longer depend on clean water

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化学 高校生

問3で1:4になるのは何故ですか?

問1 第1章 理論化学 §3 物質の変化 §3-4 酸化還元反応 酸化剤:I2+2e- → 2I... ① 還元剤: 2S2032-S,O2 +2e- ①+② : I2 +2S2O32-2I+SO2- I2+2Na2S2O32I+SO2+4Na+ I2+2Na2S2O32NaI+Na2SO 問2 D 問3 *** H+S+HS+nS ふ 1-2-1 こ Iを還元剤として用いて、 酸化剤である MnO(OH)。 に固定されたO2を定量するヨウ素) 還元滴定である。 2Mn(OH)2 +02→2MnO (OH)2) MnO(OH)2 +21 +4H+ → Mn2+ +₁₂+3H₂O I2+2Na2S2O3→2NaI+Na2SO より、(O2の物質量): (Na2S203 の物質量) =1:4である。よって、 DO × 10-3 [g/L] 32.0 [g/mol] H+¥600+HS+10 -×100×10-[L]×4=0.0250[mol/L]×3.85×10-[L] VigA類・ BAS+10 ∴. DO =7.70mg/L Zn-Zn +20 |Comment ・酸化還元滴定によってDO を求めるこの方法をウインクラー法という。 (イ)の水酸化マンガン(II) Mn(OH)2が酸素 O2 を固定する反応は酸化還元反応である。 TM10- 酸化剤: O2 +4e→202- ・③ (02-イオンの形成) 還元剤 : Mn2+ → M →Mn+ +2e-… (塩基性条件下) 千丁中都木 金 ③ + ④ × 2:2Mn2+ +02 → 2Mn4 + + 202- 2Mn(OH)2+02→2Mn4+ +202 +40H <<<<IA<gM<g\<69< ∴.2Mn(OH)2 +O2 →2MnO (OH)2 ・(ウ)のヨウ素遊離反応は酸化還元反応である。 酸化剤: MnO (OH)2 +4H + + 2e → Mn2+ +3H2O ... ⑤ (酸性条件下) では H 還元剤: 121-1 +2 ...6 ⑤ + ⑥より、 MnO(OH)2 +2I- +4H+ → Mn2+ + I +3H2O ただし、(イ),(ウ)の反応式は問題に与えられるため、暗記は不要である。 0129

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