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英語 高校生

分かる方教えてください!

What is the passage My first date with my girlfriend was a movie. I think we went to a movie called "Jackie" but to be honest, I am not entirely sure. There wasa very old and very cheap movie theater in the town that we both went to mainly about? A. Will's horrible first university in. I/ went to this movie theater with other girls sol am not sure why I stayed with my girlfriend for so long. The movie wasn't even very good. Nevertheless, we held hands in the movie and we are very happy together today. Something about that movie must have been the reason we are still together. I guess you should take your future partner to a cheap movie and you can be happy just like I am! date. B. Will's old girlfriends. - C.Will's advice based off of experience. |D.A bad movie. Wheneverl go to a restaurant in Japan, I always say, "おすすめは何ですか"./ can't read Japanese so I never mainly about? can understand what the menu says. My strategy usually works very well. I usually get the most delicious food at the restaurant and l don't have to worry about choosing what I want to eat. However, there was one time that my plan did not work. I was in a very small town which was close to Wakkanai. My girlfriend and I were very hungry and we saw a ramen restaurant where we could eat lunch. We went into the restaurant What is the passage A. Will's best food in Japan. B. Will's plan at restaurants in Japan. C.Will's love of sea snails. and l asked for the recommendation and the waitress said something in Japanese I couldn't understand. Without thinking, I said "はい". When my food arrived, I was very disappointed. I had said yes to miso ramen with sea snails in it. I love Japanese food, but I hate sea snails. My strategy did not work so well that day. D. Will's vacation to Wakkanai.

未解決 回答数: 1
数学 大学生・専門学校生・社会人

位置を2回微分すると、加速度になるんですか?

1OROY m m 0 0 9(t) 図1 単調和振動子。 復元力 F はF= ーky(t) であるとする.ここでk>0はバネ定数と呼ばれる与 えられた物理量である. ニュートンの法則(カ=質量× 加速度) を適用すると, ーky(t) =D my" (t) が得られる。ただしy" という記号でyのtに関する 2階導関数を表すものとす る。c= Vk/m とおくと, この2階常微分方程式は g"(t) +c9(t) =D0 となる。方程式(1) の一般解は, a, b を任意定数として 9(t) = a cos ct+bsinct により与えられる。明らかに, この形の関数はすべて方程式 (1) の解になってい る。そしてこの形の解のみがこの微分方程式の 2回微分可能な解になっている。 その証明の概略は練習6で述べる。 上述の y(t) を表す式のなかで, cは与えられた定数であるが, a, bはどのよ うな実数でもかまわない. この方程式の特別な解を決める場合, 二つの未知定数 a, b を考慮に入れた二つの初期条件を課さねばならない. たとえば物体の最初の 位置 y(0) と初期速度 y/'(0) が与えられれば, 物理的な問題の解は一意的となり, y(0) sin ct 9(t) = y(0) cos ct + C により与えられる. 容易にわかることであるが, ある定数 A>0と φERで, a cos ct + bsin ct = Acos (ct - 4) をみたすものが存在する. 上に述べた物理的な解釈に基づいて, A= Va? +6? をこの運動の「振幅」 cを「固有振動数」 (aを「位相| (これは ?Tの整数倍

解決済み 回答数: 1