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英語 高校生

5つの下線部の正しい訳を教えて欲しです。 至急お願いします🚨🙇

Unit 12 Change the World Basic A few years ago, an obesity* researcher at the University of Washington-named Adam Drewnowski ventured into the supermarket to solve a mystery. He wanted to (1) figure out why (2)poor people were more likely to suffer from obesity in America. Obesity is, as you know, mainly caused by taking in too many calories. For most of history the poor have typically suffered from a shortage of calories, not an excess. So why do the people with the least amount of money to spend on food tend to be overweight today? 目 Drewnowski gave himself a dollar to spend, using it to purchase as many calories as he possibly could. He discovered that he could buy the most calories per dollar in the middle aisles of the supermarket, among the towering piles of* processed food and soft drinks. 3 Processed food is, in the broadest sense, any food that is changed from its natural, raw state. But here, it refers to food which has been chemically changed by using additives* such as flavors, colors, preservatives*, stabilizers*, etc., or which has been combined with other foods in a manufacturing process. Generally speaking, if the ingredients* aren't “natural,” then we consider it to be ( 3 ). Drewnowski found that a dollar could buy 1,200 calories of cookies or potato chips, which are typical processed foods, but only 250 calories of carrots. Looking for something to wash down those chips, he discovered that his dollar bought 875 calories of soda (a processed food) but only 170 calories of orange juice. 5 As a rule, processed foods are more “energy dense*” than fresh foods: they contain less water and fiber but more added fat and sugar, which makes them both (4)less filling and more fattening. 5 These particular calories also happen to be the least healthful ones in the marketplace, which is why we call the foods that contain them "junk*.” Drewnowski concluded that the rules of the food game in America are organized in such a way that if you are eating (6) on a budget, the most rational economic strategy is to eat badly-and get fat.

未解決 回答数: 1
数学 高校生

赤く丸をしたbの問題で解答の方に二階微分した後の式がなぜ(-1/4)(-1/4)(H-27)になるのか分かりません。教えてください🙇‍♀️

QA At time t = 0, a boiled potato is taken from a pot on a stove and left to cool in a kitchen. The internal temperature of the potato is 91 degrees Celsius (°C) at time t = 0, and the internal temperature of the potato is greater than 27°C for all times t > 0. The internal temperature of the potato at time t minutes can be modeled by the function H that satisfies the differential equation dH (H- (H-27), where H(t) is dt measured in degrees Celsius and H(0) = 91. (a) Write an equation for the line tangent to the graph of Hat t = 0. Use this equation to approximate the internal temperature of the potato at time t = 3. (b) Use 2017 APⓇ CALCULUS AB FREE-RESPONSE QUESTIONS (a) dH d²H dt² to determine whether your answer in part (a) is an underestimate or an overestimate of the internal temperature of the potato at time t = 3. (c) For t < 10, an alternate model for the internal temperature of the potato at time 7 minutes is the function -= − (G - 27)²/3, where G(t) is measured in degrees Celsius dG G that satisfies the differential equation dt and G(0) = 91. Find an expression for G(t). Based on this model, what is the internal temperature of the potato at time t = 3 ? 564 at (21-27) - == 2-16 To = - = (H(3)-27) 4 -64 = HB)-27 -37 = H (3) (b) _d²fi © 2017 The College Board. Visit the College Board on the Web: www.collegeboard.org. GO ON TO THE NEXT P

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化学 高校生

どうして[H₂O₂]は2乗にならないのですか?

10 5 (60)式と(62)式のように,反応物の濃度と反応速度の関係を表した式 を 反応速度式または速度式という。このとき,比例定数k, k′は rate equation 速度定数とよばれ,反応の種類が同じで、温度が一定ならば一定の値 rate constant となる。温度を変えたり,触媒を加えたりした場合には,速度定数の値 は変化する。 反応速度式は化学反応式の係数から単純に決まるようなものではなく, 実験によって求められるものである。 例えば, (58) 式の反応速度”は, 実験によって (63) 式のように表せることがわかっている。 ●参考 2H2O2 2H2O + O2 v" =k" [H2O2](k" は比例定数) -2乗ではない 問 14 A + 2B Cの反応がある。 Aの濃度だけを0.5倍にすると, 反応速度 は 0.5倍になった。 Aの濃度を0.5倍に, B の濃度を 1.5倍にすると, 反応 速度は0.75倍になった。 この反応の反応速度式を示せ。 参考 反応速度式の決定 参 p.145の と濃度を算出した。 ここで,平均の反応速度が平均の濃度に比例すると仮定する。 v = k c ( k は比例定数) で, 2H2O2 2H2O + O2 で表される反応の反応速度 このとき,各時間帯の についてんを求めると, その値 はほぼ一定となる (右表)。 時間 [s] 速度定数k [×10-/s] と求めることができる。 また, に対する をグラフに すると、右図のようになる。 これに したがって, 反応速度式はvk [H2O2] と決定でき, その値は 2.3 + 2.3 + 2.3 + 2.3 + 2.1 k= = 5 x 10™/s ≒ 2.3 x 10-2/s la [x1 (58) Op. 143 (63) X 1.6 1.4 1.2 10 0 30 60 90 120 150 2.3 2.3 2.3 2.3 2.1 絡

未解決 回答数: 1