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英語 高校生

英検準一級の要約問題です。 添削していただけないでしょうか?🙇‍♀️

英検公式サンプル問題 ⚫ Instructions: Read the article below and summarize it in your own words as far as possible in English. ⚫ Suggested length: 60-70 words Write your summary in the space provided on your answer sheet. Any writing outside the space will not be graded. From the 1980s to the early 2000s, many national museums in Britain were charging their visitors entrance fees. The newly elected government, however, was supportive of the arts. It introduced a landmark policy to provide financial aid to museums so that they would drop their entrance fees. As a result, entrance to many national museums, including the Natural History Museum, became free of charge. Supporters of the policy said that as it would widen access to national museums, it would have significant benefits. People, regardless of their education or income, would have the opportunity to experience the large collections of artworks in museums and learn about the country's cultural history. Although surveys indicated that visitors to national museums that became free increased by an average of 70 percent after the policy's introduction, critics claimed the policy was not completely successful. This increase, they say, mostly consisted of the same people visiting museums many times. Additionally, some independent museums with entrance fees said the policy negatively affected them. Their visitor numbers decreased because people were visiting national museums to avoid paying fees, causing the independent museums to struggle financially.

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数学 高校生

(1)でこのやり方でやったらダメな理由を教えてください

「基本 例題 178 対数の表現 ①の (1) log23=a, log35=bのとき, 10g210 と 10g 1540 を a b で表せ。 1 (2) logxa= " logx b= 3 logxc= 8 1 24 のとき, 10gabecxの値を求めよ。 [名城大] [久留米大] (3) a,b,c を1でない正の数とし, logab=a, logbc=B, logca=yとする。 このとき, aβ+By+ya= 1 1 _+ + a B 1 r が成り立つことを証明せよ。 基本 177 指針 (1)10, 15, 40 をそれぞれ分解して,2,3,5の積で表すことを考える。 log210=logz(2.5)=1+10g25 底の変換公式を利用して, 10g25をα 6で表す。 また, 101540 は, 真数 40=52 に着目して2を底とする対数で表す。 (2)10gabcx= 1 logx abc である。 logxabc の値を求める。 (3) 右辺を通分すると, 分母に aβy が現れる。 これを計算してみる。 (1)10g210=10gz (2.5)=log22+log25=1+log25 建答 ここで log25= log35 log32 =log23.10g35=ab log32= 10g23 よって log210=1+ab 前ページ検討も参照。 log240 また log 15 40= log2(5.23) log25+3 == log2 15 log2(3.5) log25=ab (前半から) log2 310g25 = ab+3 ab+3 = a+ab a(b+1) (2)10gxabc=logxa+10gx6+10gxc= 1 1 1 + + 3 8 || 24 12 よって logabc x= =2 logx abc (3) + + a 1 B 1 Y aβ+By+ya aby aβy=logablog.clogca=logab• ① loga C =1 2 log. = (3)別解 1 log■ aβ=logablog.c=log 同様に βy=log.a logab logac ra=logcb 1 1 1 したがって であるから,①から + + a B =aβ+By+ya が成り Y 立つ。 したがって, 等式は証明された。 (左辺) =logac+log.a+log =1+1/+1/ B

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