この全文訳の内容がよく分かりません。 特に同様に誤解を招きそうであるという所が前文の内容と同様にとすると前文の内容のとこから誤解を招きそうというのが出てきたのかが分からないです

57 形容詞的 <to V>1~3 次の英文の下線部を訳しなさい 238 It is easy to see why many people visiting Japan for the first time talk and write of it just in terms of unresolved contrasts - computer and the kimono, the chrysanthemum and the sword. On the other hand, any attempt to find a single category to include all the phenomena of contemporary Japanese social and political life is likely to be equally misleading. 114 なぜ why S(形) Vi C S (真)→(不) (Vt) (O)→(疑・副) (こと)は である 簡単 ことを理解する 2 or It is easy (to see この例題の中にも, <to ⑩> がいくつかありますね。 第1 文の to see 「解 法文の to find to include など。 それぞれどんな使われ方をしているかを考え abnil or risul ながら、 解釈していきましょう。 初めて (for the first time) talk and (M) Vi① (等) 語ったりまた書いたりする(か)について 日本 write (of it) Vi② (M) ~という」 日本 多くの人たちがを訪れる many people visiting Japan S OR 分形) (V) (0) re まさに~の点から 理解しにくい 対比 (just in terms of unresolved contrasts ~)]). (群前) (名) the (玉川大) >*.3JT () 同人 おおきます。 (形) Jet COX to see は It との関係で楽に考えられますね。 もちろん, 形式主語のIt です。why 節は see の目的語になっていますが、あっさり「なぜ〜か」と訳すといいでしょう。 第2文では,前課の既習事項を生かして, category to include は「含む(ような / POR べき)カテゴリー」としましょう。 attempt は第2文の主語ですが, to find を 「見つ けるべき/ための)」 とするとしっくりきません。 attempt (名詞) は 「試み→~ 「ようとすること」と解されるために, attempt to find は ｢見つけようとする試み」 → METZE 【例題:語句 in terms of 群前の観点から/unresolved 形説明しがたい/chrysanthemum 菊/category 名認識の枠組み / phenomenon 現象 (phenomena は複数形)/ misleading 形誤解を招く [V] vevnoo \[!! 「見つけよう 他 (On the を (to inc (木) ( (of cor (前) 名詞の内 ときは, ｢~ があるとき desire, pl attempt を ことになり is like V C 《全文訳》 といっ が多い 社会, つけよ 演習 5 Many: English c that they kokusaig of everyt 演習: 語句 優越

BからDの解答と解説が欲しいです。どなたかお願いします。一部暗くてすみません。

〔B〕 〔彼はうわさ話ばかりしていたので演劇クラブから追い出されたと言われてい る。 It is said that (32) ( the drama club. 7. getting I. kicked out ア・ everyone イ. his オ.led I. liked )()( 〔C〕 彼女の性格はクラスのみんなから好感を持たれるほどのものだった。 Such ( 34 ) ( ) ( 35 )( )( )( ) her. イ. her nature ウ. in her class 才.that 力 was P )..( ) ( 33 ) of ウ. his constant "gossiping ゴシップ 力.to 〔D〕誰も私に知らせないでパーティを準備してくれていたのに、その計画に気付 いてしまって申し訳なく感じた。 Since()( ) ( 36 ) ( felt bad about finding out about the plan. 7 anybody イ. being I. the party オwas ) ( 37 )( ) telling me, I ウ prepared #without

3行目、with whomの部分は関係副詞ですよね？ どのように訳せばいいか、文構造のとり方を教えてください🙇‍♀️

次の英文を読んで、設問に答えよ。 第1講 e.g. The *therapeutic use of pets as companions)has gained increasing attention in recent years for a wide variety of patients people with AIDS or cancer, the elderly and the mentally ill (Unlike people, with whom our interactions may be quite complex and unpredictable, animals provide a constant source of comfort and focu X S X 5 for attention. Animals bring out our nurturing instinct. They also make us feel saf (1) and unconditionally accepted. We can just be ourselves around our pets. らしきおこさまた stress-induced symptoms)<I x Research has shown that pet ownership can reduce $$E surgen 343 a study, people undergoing *oral surgery spent a few minutes watching tropical fis O' in an aquarium. Their relaxation level was measured by their blood pressure, muscl わかった Xp 10 tension, and behavior. It was found that the subjects who watched the fish wer

even those about...からの文構造と訳が分かりません どなたか心優しい方、教えてください🙏

4 ( )内の適切なものに○をつけなさい。 A new series of novels (1)(which, which are set in the 15th century, has made people (2) (who who ) would not usually read about history become interested in *Medieval Britain. That was a time (3)(which/ when there were constant battles for time power. The reason (((why/how) the books are so popular is that the author (5) who who used to be a history teacher, shows us how people lived then, by bringing to life the characters of that era, even those about (6) who / whom/) little is actually known.

10,68の答えがどうしてこのようになるか教えてください。 分野は重積分のストークスの定理です

By Green's theorem in space (divergence theorem). Prove that that (V x A) - n ds for any closed surface S. S Prove that 10.66. dS ff n ds = 0. where n is the outward drawn normal to any closed surface S. (Hint: Let A = Oc, SS S where c is an arbitrary vector constant.) Express the divergence theorem in this special case. Use the arbitrary property of c. 10.67. If n is the unit outward drawn normal to any closed surface S bounding the region V, prove that fff div n dv = S V Stokes's theorem 40.68. Verify Stokes's theorem for A = 2yi + 3xj - z²k, where S is the upper half surface of the sphere x² + y² + ² = 9 and C is its boundary. Ans. Common value = 9T 10.65. , y = 0,

【緊急！】化学基礎 物質量を求める公式が2つあるのはなんでなのか教えて欲しいです。 後、違いも教えて下さるとありがたいです🙇

62 物質量 (mol) A アボガドロ定数と物質量 化学反応は,物質を構成する原子・分子・イオンなどの粒子の組 を考えるときは,多数の粒子を一定数の集団として考えると便利であ モル 11 毎モル 6.02×1023 (個)の数を1mol ｣ と定義する。 この粒子 1molの個数を そこで、 膨大な粒子の数をはかる mol という単位記号を定め、 ボガドロ定数 NA といい, 単位は/molで表す。 Avogadro constant 1mol:6.02×1023(個) の粒子の集団 アボガドロ定数NA [/mol] :6.02×1023/mol amount of substance mol を単位記号として表した物質の量を物質量という。どんな原 分子イオンでも, 1mol に含まれる粒子の数は,常に 6.02×10237 粒子数 物質量[mol] アボガドロ定数NA [/mol] 1mol 2 mol 3 mol この数 (6.02×1023)×1 (6.02×1023)×2 (6.02×1023)×3 33 物質量の関係粒子を1mol, 2mol…という集団を単位として数える。 3 物質量に関する次の各問いに答えよ。 物質量で表すとき アボガドロ定数 N =6.0×1023/mol の粒子の種類を必 (1) 二酸化炭素 CO2 2.0 mol に含まれる二酸化 炭素分子の数はいくつか (2) 3.0×1024個のアンモニア分子NH3 の物質量 は何mol か。 (3) 水分子H2O1.5mol に含まれる水素原子H B

この答えを教えてください‼︎

What Are the Key Points? Dr. Amano's skill is a. a gift from God. 1:41" b, the result of natural talent. c. the result of hard work and constant practice. 2 Dr. Amano's father had to have his artificial heart valve replaced. Dr. Amano a. performed the operation himself. b. observed the operation from start to finish. c. told his father that it was too dangerous to have such an operation. 3 When Dr. Amano says, "The word 'compromise' is not in my dictionary," he means that a. he cuts corners. b. he needs to buy a better dictionary. and c. he always makes the best possible effort to save lives. 4 Dr. Amano feels that a doctor should a. always carry a stethoscope. b. establish good relationships with patients. c. cure the disease and not waste time being “nice” to people. Summary Complete the summary by filling in the blanks. Dr. Amano Atsushi is one of the most famous doctors in Japan. He has been called "the (1. ) with God's hands." Dr. Amano, however, does not believe that his success comes from God. He attributes it to hard work and (2. ) practice. Success did not come easily to Dr. Amano. He failed the university entrance exams for three consecutive years. After finishing medical school, Dr. Amano went to work at a general hospital. He was single-minded in trying to (3. ) his skills. After long work days, he practiced (4. Dr. Amano feels that one of the most important things for a doctor is to establish ) all through the night. good (5. ) with his patients. Dr. Amano accepts his fame. He hopes it will inspire young (6. Food for Thought ) surgeons. ② “God's hands” と呼ばれるほどの技術は、一部の天才だけが習得可能なものである。 ① “God's hands” と呼ばれるほどの技術は、だれにでも習得可能なものである。 このふたつの主張につき、テキストの内容にそ 1

1行目の文型ってこれで合っていますか？

V 10. Read the following the passage and answer the questions. Our bodies are designed (to deal with short-term stress., s.) When we are under stress, *adrenaline flows through our bodies and our *immune system is heightened. Short-term stress, such as a having to give a speech, has a defined endpoint, and afterward the adrenaline *surge can stop and the body can return to normal. Long-term stress, ( 1 ), such as being overwhelmed by one's job, has no defined endpoint, and the state of constant alarm (2) [ body / forced / into /

問2 の答え合ってますか？ 教えて下さい🙇‍♀️┏○" 気体の状態方程式 の問題です

図5 ボイル・シャルルの法則と気体の状態方程式の関係 例題 2 27℃ 4.5×10Pa で, 8.3L を占める気体の物質量は何molか。 ただし, 計算を簡単にするため, R = 8.3×103Pa・L/(K・mol) とする。 解答求める気体の物質量をn [mol] として,P=4.5×10°Pa, V=8.3L, R = 8.3 × 10° Pa・L/(K・mol), T= (27 + 273) K = 300Kより 気体の状態方程式 PV=nRTの式に単位に注意して,数値を代入する。 4.5 x 10Pa x 8.3L = n × 8.3× 10Pa・L/ (K・mol) ×300K 4.5 x 10Pa x 8.3L = 1.5mol n 8.3 x 10°Pa・L/ (K・mol) × 300K 答え 1.5mol 問 2 酸素 0.10molを4.0Lの容器に入れて127℃に保つと, 圧力は何Paを示すか。 アボガドロの法則: Avogadro's law 気体定数: gas constant nRT P ⇒P. 21 2 V 40 7 0.1×8.3×10 X (213+ (21) 8:3 0.1×400×8.3×10 332 8.3 33.2×10 8 (3) 2 TO 0₁ 27 ボ 813×104 pa RT P

訳して欲しいです！

ep Billy, Goat, and Gruff Rilly. Goat, and Gruft have stuck by Bo's side through the vears. These porcelain sheep have a few cracks and scratches. but they can always count on Bo to take care of them. Opicer Giggle McDimples Bo's pint-sized confidante and Constant companion is proof that size doesn't matter.. Giggles is sharp, spirited, and always ready for action!