✨ Best Answer ✨
log{f(x)}の微分は 1/f(x) × f'(x) なので
fx(x,y)
= 4log(y/2x) + 4x･(2x/y)･(-y/2x²)
= 4log(y/2x) -4
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✨ Best Answer ✨
log{f(x)}の微分は 1/f(x) × f'(x) なので
fx(x,y)
= 4log(y/2x) + 4x･(2x/y)･(-y/2x²)
= 4log(y/2x) -4
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are also looking at these questions 😉
f'(x)の値ってあってますか？