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f'(x)>0 つまり 3(x+1)(x-1)>0 の解は
x<-1、x>1
f'(x)<0 つまり 3(x+1)(x-1)<0 の解は
-1<x<1
だからです。

成瀬

なるほど...!!!
ありがとうございます!🙇🏼‍♂️

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