(sinθ)^3+(cosθ)^3
=(sinθ+cosθ)(1-sinθcosθ)
sinθ+cosθ=a
1+2sinθcosθ=a^2
∴a(1-(a^2-1)/2)
Answers
Were you able to resolve your confusion?
Users viewing this question
are also looking at these questions 😉
Recommended
詳説【数学Ⅰ】第一章 数と式～整式・実数・不等式～
9001
117
数学ⅠA公式集
5751
20
詳説【数学Ⅰ】第三章 図形と計量（前半）～鋭角鈍角の三角比～
4581
11
【セ対】三角比 基礎〜センター約8割レベル
985
3