△AFDの面積を2とすると
△FBD=3
△ABD=△AFD+△FBD=5
△ABD=△CDB=5
平行四辺形ABCD=△ABD+△CDB=10
よって3:10
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△AFDの面積を2とすると
△FBD=3
△ABD=△AFD+△FBD=5
△ABD=△CDB=5
平行四辺形ABCD=△ABD+△CDB=10
よって3:10
Users viewing this question
are also looking at these questions 😉