Mathematics
Senior High
Resolved
t＝10.7
になってしまいます。
求める温度を[℃]とすると, 熱量の保存より, Q=n
Q=mL を用いて,
100×4.2×(20-t) =D 10× (3.3×10°) + 10×4.2× (t-0)
ゆえに,t=11.0…=11[℃]
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