Question

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2³
(248x3
(1) (3x+4) X3x (+) (4a-6)x5a (3) (42+58)x(-27)
=9x²+3x7
-20a-5a6
8x10x7
E
(4) Fa (3a-2)
= 150-100
● (1)-za(-at36)
→
(5) 2x(3x744) (6)-3b (6a-56)
= 6x+8x4
= -18abt 156°²
(8) (X+Y-5) X9X (9) - 4a(20-3b+5)
= 3x² + 3x7-15x = fa+kab 200
E (1) (Px²+6x) = 2x
((0) 2x ( -=x+44-3)
-2x+8 xs-6x
(-) (10d²-50) = 50
= 2a+1
(5) (-3x² + 9x) = (-32)
= 4x+3
(3) (yax +904)+ 30 (47)/ 40x-ray) = (-40)
=X+24
(6) (2a6+6a6²) + 2ab
= a +36
13
(10) 1923-62²4) = 3 x ( ) ( - 8 F + 4) = (-+)
******
= 157-1007
E
(3) (31-6x8 ) = 3-t (4) (182²6 +1206) + (-396)
=2X-47
150-106
Wik
****

Answer 1

✨ Best Answer ✨

kabukuwa

1(12) 2a-1
後は、よくできました💮