Mathematics
Junior High
（3）の解き方を教えてください
(3)
(4)
a6f4
7
(x²y4) ³ (6x³y6) 2
3
X
(62³)2) = (-22)
÷
24
(a²6 ×
{
b
4a
ab32
3
3
6
X
x
28y7
(- ab) ³
14
)
3966(1)
Answers
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