Mathematics
Junior High
Solved

これどうやって解くんですか!

[3] a+b= 10,a6=7のとき, a²+3ab+b2 の値を求めなさい。 a²+3 ab + b ² = (a + b)² + 3ab a² + 2ab + ab + b 100 +21 =121
因数分解

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