Mathematics
Junior High
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(3x－3)(3x－11) からどうやって 3(3x－11)(x－1) にするのか教えてください🙏
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(7) (3x-4) ²-6 (3₂-4) -7
=9x²24x+16-18x+24-7
=9x² - 42x133
=(3x-3)(3x-(1)
3 (3X-11) (x-1) 67
=
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![中学3年2次方程式の問題です。
問題文の[1つだけ整数の解をもつとき]と[2つの異なる整数... - 1](https://d1e9oo257tadp1.cloudfront.net/uploads/qa_question_image/file/1808181/thumb_l_webp_17834198910490.webp?Expires=1783604144&Signature=OxBMr1UkQWWLrntPqdP5avX9yOaVd18dw-0biN6ExjL7JV278hfGc-9x2BvP-4r8bxjbdNDMr03J3JvkNFdcEaHnr8AazSgvoffE-ZWBN2sp4Awpj2imJzwa6sMf3urtGP4nbWm5wRuKXCDlKONsJEqa~4BEVA8KfEHxXzm~cVxRnP5XLAYxWoGt--jWoOmw81YU5Vo79usypioIZfnsDOw-htI58Jljz25dwq4kxt5BKYLaIWD0L3wyBm0iAXlWqRJj3Fb4lTrWq4we2yBg~3jzStnSU-eWgxVAt3Gwp7Y-fhswLVrccrYTjWhSS6h3rRhDO0rQL1mGMW2fGyhrcg__&Key-Pair-Id=K2W722D70GJS8W&Expires=1783604144&Signature=EVP3GDUEqxRiNeaYS-f29SEulKs~KwjdwDS94pSPYzx6q5nR-QSf8RZ~P4CGH~ND67b79n3YMOrhYE4NXP5lvzs5ad3GYAA6rTkiMB42CMww0d5IqDEpP5fJXI4necP646bDJ2FdboyvYi-tH5SOy9na1ssVfCVLjfLnFb4H8GKNACEK6pUMOvbKI~06AWW8eQHKJbRt7lTWmkbdy-9c~6JpS3gbekrTJXVoXmaViTBOyuvfAoN3~SdHF90TR-Isq3tb9mmMu954qED0uZzJMyaqd-ID2NVJfkSuLnji2XUm5Z6CJMpmDCm6qbnVyfS1tGjaSvz0vDmP322Gv2boqQ__&Key-Pair-Id=K2W722D70GJS8W)
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