✨ Best Answer ✨
(e^x / x)'
={(e^x)'×(x)-(e^x)×(x)'} / (x^2)
=(xe^x-e^x) / (x^2)
=(x-1)e^x / (x^2)
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✨ Best Answer ✨
(e^x / x)'
={(e^x)'×(x)-(e^x)×(x)'} / (x^2)
=(xe^x-e^x) / (x^2)
=(x-1)e^x / (x^2)
Users viewing this question
are also looking at these questions 😉
