TVET CHNS,Eng,Maths
Senior High
Resolved
求第四題過程 謝謝🙇
3. 不等式(x + 2)(2 - 3x) ≤ 0 之解為X-201X2號
(X+2)(3x-2)20
古言
4. 設f(x)為二次函數,且f(x)<0之解為-7<x<19,則不等式(-3x + 1) < 0 之解為
一子
(X+7)(HKO
(-4X+1)=12(-4x+12133<0
-b<x<=
X=12X-133<0 16X-8X+1+48X-12-13320
11.7² +407, -144 20
Answers
Were you able to resolve your confusion?
Users viewing this question
are also looking at these questions 😉
謝謝~