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(1)
A(-1,1)よりa=1

(2)
y=x^2上の点A、Bのx座標がそれぞれ-1、3なので、
直線ABの切片は-1×(-1)×3=3となるからC(0,3)

(3)
△OAB=AとBのx座標の差×OC×1/2となるから
△OAB=4×3×1/2=6

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