Mathematics
Senior High
Solved

赤で囲った式は、どうやって導き出したのか分かりやすく教えてほしいです!青線で引いた途中式を読んでもよく分かりませんでした…😣🙏

2n (3) Σ k² k=n+1
(3) 2n Σ k² = (n + 1)² + (n + 2)² + (n+3)² +•••+(2n)² k=n+1 = = = = = {1² +2²+3²+...+n² + (n + 1)² +...+(2n)²} - (1² +2²+3²+...+ n²) 2n n Σk² - Σk² k=1 k=1 (-) 1 • 2n(2n + 1) (2 • 2n+1) n(n+1)(2n+1) 6 n(2n+1){2(4n+1)−(n+1)} 1 I onl 6 1 6 n(2n+1)(7n+1) - 6
数列 数b

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