Mathematics
Senior High
Solved
赤で囲った式は、どうやって導き出したのか分かりやすく教えてほしいです!青線で引いた途中式を読んでもよく分かりませんでした…😣🙏
2n
(3) Σ k²
k=n+1
(3)
2n
Σ k² = (n + 1)² + (n + 2)² + (n+3)² +•••+(2n)²
k=n+1
=
=
=
=
=
{1² +2²+3²+...+n² + (n + 1)² +...+(2n)²}
- (1² +2²+3²+...+ n²)
2n
n
Σk² - Σk²
k=1
k=1
(-)
1
• 2n(2n + 1) (2 • 2n+1) n(n+1)(2n+1)
6
n(2n+1){2(4n+1)−(n+1)}
1
I onl
6
1
6
n(2n+1)(7n+1)
-
6
Answers
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ありがとうございます!✨