2y-1をAとおくと
(x-(2y-1))(x+(2y-1))
=(x-A)(x+A)
=x^2-A^2
=x^2-(2y-1)^2
=x^2-(4y^2-4y+1)
=x^2-4y^2+4y-1
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2y-1をAとおくと
(x-(2y-1))(x+(2y-1))
=(x-A)(x+A)
=x^2-A^2
=x^2-(2y-1)^2
=x^2-(4y^2-4y+1)
=x^2-4y^2+4y-1
Users viewing this question
are also looking at these questions 😉