✨ Best Answer ✨
沒有才對吧
h'(0)=g'(f(0))f'(0)
其中
f(0)=3
f'(x)=4x-1 → f'(0)=-1
g'(x)=3x²
所以
h'(0)=g'(3)(-1)
=3·3²·(-1)
=-27
為什麼f(0)那個地方有2次~~
謝謝
✨ Best Answer ✨
沒有才對吧
h'(0)=g'(f(0))f'(0)
其中
f(0)=3
f'(x)=4x-1 → f'(0)=-1
g'(x)=3x²
所以
h'(0)=g'(3)(-1)
=3·3²·(-1)
=-27
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