Mathematics
Senior High
Resolved
想知道第二小題為何這樣列式
16 #
H = 1 x ===
例
131) 270 Sin 0 + CO4 0 = Ź
8/05
fi (1) sin x cos (2) Sin³o, cos³o
Sino + Cos³0 = 1 (=\
S018 (Sint + Coso) = (Siño + 2x sing x coso | C50 = 12)²
(1)
=
1 + 2 x
sin
x
↓移項
:
cos 0 = 2x sing×650=4-11-{{}}
=> Siu 0 × cos O - - — #
=
-(2)_Sin³y +Cos³0 = (Sind+ Cosoi (siñ³o - sino cost + cos³) = = (1+(+})})
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