Question

nanaco

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19
=16-627
⑦a=3-√5b=3+√5のとき、
(1) a2-2a-3
05
a
-39
-3
+(9
+1
1)
"
=2a
(a-3) (a+1)
(3-√5-3)(3-√5+1)
=(-15) (4-1)=4-215
(3) a2-b 2
分配
= (a+b) (ab) (72
(a+b)(ab)
= (3-√5+3+ √5) (3-√5+3-√5
=(6)(-2)
-12.5

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Answer 1

✨ Best Answer ✨

きらうる

(3)
(a+b)(a-b)
＝(3-√5+3+√5)×{(3-√5)-(3+√5)}
＝(6)×(3-√5-3-√5)
＝6×(-2√5)
＝-12√5