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  5. (x－8)(2x+5)=0の二次方程式の解...
Mathematics
Junior High
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恋菜
恋菜

(x－8)(2x+5)=0の二次方程式の解き方教えて欲しいです(><)💧

至急‼️‼️

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✨ Best Answer ✨

BaSO4
BaSO4

x×2x+x×5-8×2x-8×5
=2x^2+5x-16x-40
=2x^2-11x-40

BaSO4
BaSO4

方程式が成り立つのは
x=8,-5/2

恋菜
恋菜

なるほど‼️丁寧にありがとうございます😭💖

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