1/x=2/(√3+1)
=2×(√3-1)/((√3+1)(√3-1))
=2(√3-1)/(3-1)
=√3-1
p=x+1/x+3
=(√3+1)/2+(√3-1)+3
=(√3+1)/2+(2√3-2)/2+3
=(3√3-1)/2+3
=(3√3+5)/2
わからなかったです。教えてください🙇♀️
1/x=2/(√3+1)
=2×(√3-1)/((√3+1)(√3-1))
=2(√3-1)/(3-1)
=√3-1
p=x+1/x+3
=(√3+1)/2+(√3-1)+3
=(√3+1)/2+(2√3-2)/2+3
=(3√3-1)/2+3
=(3√3+5)/2
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