Mathematics
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x²+y²+3x²=4がどう式変形したら楕円の式になるのでしょうか?🥲

(5) r2(1+3cos20)=4より r2+3recos20=4 r2=x2+y, rcose = x であるから x2+y2+3x2 = 4 0=02 2008 x. (ε) よって x2+ :1 4 一楕円

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ありがとうございます!!おかげで解けました!😭

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