Mathematics
Senior High
Solved
x²+y²+3x²=4がどう式変形したら楕円の式になるのでしょうか?🥲
(5) r2(1+3cos20)=4より
r2+3recos20=4
r2=x2+y, rcose = x であるから
x2+y2+3x2 = 4
0=02
2008
x. (ε)
よって
x2+
:1
4
一楕円
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ありがとうございます!!おかげで解けました!😭