TVET CHNS,Eng,Maths
Senior High
Resolved

求解 高職數B

8.在坐標平面上,過點(2,-1)且與直線+2=1垂直的直線方程式為 3x-4y=103。 3 4

Answers

✨ Best Answer ✨

x/3 + y/4 = 1
=> y = (-4/3)x + 1
令所求:y = (3/4)x + b
-1 = (3/4)(2) + b
b = -5/2
y = (3/4)x - 5/2
3x - 4y - 10 = 0

Post A Comment
Were you able to resolve your confusion?