Mathematics
Junior High
求解
4
R
(
亮面 38 (S)
☆ 如右圖,△BDE 為等腰直角三角形,若ADAB,CEBC,且D
AD=7,CE=4,則DE=
2
549+16
= √65
√√30
=
130
E
NAJJ
L
A4B7C
Answers
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