微分の性質を前提とします
F'=f, G'=gとすると
上
(F+G)' = F'+G' = f+gより
左辺 = ∫(f+g)dx = F+G
一方、右辺 = F+G です
下
(kF)' = kF' = kfより
左辺 = ∫ kf dx = kF
一方、右辺 = kFです
Mathematics
Senior High
これらの証明をお願いします🙇♀️
不定積分の公式②
[(f(x)+g(x)}dx=ff(x)dx+fg(x)dx
Skf (x)dx=kf f(x)dx
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