Mathematics
Senior High
Solved

ここまでは解けたのですがこの先でどのようにa b cを求めればいいのか分かりません

ax²+bx+3=(x-1)(x+1)+c(x+2)² 2 x² - 1 + C (x² + 4x + 4) 2 = x² - 1 + c x² + 4 x C + 4 C 2 + 4c x + 4c-1 ((+c)x+ 1+c=a 4c=h 4C-1=3

Answers

Were you able to resolve your confusion?

Users viewing this question
are also looking at these questions 😉