x(x＾2－4)＋(x＾2－4)
＝(x＋1)(x＾2－4)
※右の( )はまだ因数分解できます
8はaについてまとめると
(b＋c)a＾2＋(b＾2＋2bc＋c＾2)a
＝(b＋c)a＾2＋a(b＋c)＾2
共通因数a(b＋c)でくくると
＝a(b＋c)(a＋b＋c)
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![中学3年2次方程式の問題です。
問題文の[1つだけ整数の解をもつとき]と[2つの異なる整数... - 1](https://d1e9oo257tadp1.cloudfront.net/uploads/qa_question_image/file/1808181/thumb_l_webp_17834198910490.webp?Expires=1783945729&Signature=RJ0TI7OpFD89ii8JRvd5F92Z1yE~hwTpcLp2vFmL2HkPq53oiNL3i2v9n-fNZnDq1v9BpwixhHasDNlw4hcU8Y7yCRg2I789P56dZv-qI0EPxzGtUbaPeuB0EFxk9zup7MBz3uxj2kEgFcqYVBfHJmBXxbhlUuOq08RHmDPWgulwwiBxS3S6QDC6qzX9UW4g9-Wt7KoC0Pp~hgBp2b2-yhJPzRj6MzAgGjEkdLelxvEBEDOGjIqFF29KzUHpSIhVc912RbkIPm-2DwOmP-DG2cij5XKPuEuzhO5H1NOaGzv04a9gVJ1xAzJmxFJcxOGdzaWxgKz0mYH~PotwXMxLLA__&Key-Pair-Id=K2W722D70GJS8W&Expires=1783945729&Signature=nwVh5uB7~QHDjMt5TyaSJUHSDfTPsquoPVG-9FBCxsphf7QU1vYFaN~55B7qk79izhvnr5uMLtCp5KMMvb~tvOVdy-ZE5XTqJkihDTzIP8OH9wM-h6iiLahnx12DET9mGlDWNFIBPX8VtjPh-7jzkK7edglRfxvG7HlAzC~rjrG3aIBVtZWC3dRFw1ZC61BQFtuYmJ05ZK4eBXD6ELA1TJER4t5YaG5lQxWFff390o5p4r9T5mh8KnHaadrFH0Hk4KlA7dhpu3W3wZAk4TO5H9wTM3frabBioYfoNloWjRyAVzXHFpKmFvuqs8qIMa1J~cXjmqn~dzQGS4kzUjAN7A__&Key-Pair-Id=K2W722D70GJS8W)
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