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3乗の公式です
・(a＋b)³＝a³＋３a²b＋３ab²＋b³
・(a－b)³＝a³－３a²b＋３ab²－b³
・(a＋b)(a²－ab＋b²)＝a³＋b³
・(a－b)(a²＋ab＋b²)＝a³－b³
8a³を(2a)³と考えます
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3乗の公式です
・(a＋b)³＝a³＋３a²b＋３ab²＋b³
・(a－b)³＝a³－３a²b＋３ab²－b³
・(a＋b)(a²－ab＋b²)＝a³＋b³
・(a－b)(a²＋ab＋b²)＝a³－b³
8a³を(2a)³と考えます
Users viewing this question
are also looking at these questions 😉
