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✨ Best Answer ✨

PQ//RSより∠CAQ=∠ACR
また ∠ACR=∠ACB+∠BCR=∠ACB+22°
よって ∠ACB=58°
△ABCはAB=ACの二等辺三角形であることから
∠ACB=∠ABC=58°
よって ∠CAB=64°

∠x=180°-(∠CAQ+∠CAB)=180°-(80°+64°)
=36°

<終>

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