3x^2+x(7y－16)+2y^2－7y+5
=3x^2+x(7y－16)+(y－1)(2y－5)
1・・・(2y－5)
3・・・(y－1)
=(x+2y－5)(3x+y－1)
Answers
Were you able to resolve your confusion?
Users viewing this question
are also looking at these questions 😉
Recommended
【数学】覚えておいて損はない！？差がつく裏ワザ
11433
87
【夏勉】数学中3受験生用
7362
105
【テ対】苦手克服!!証明のやり方♡
7066
61
【夏まとめ】数学 要点まとめ！(中1-中3途中まで)
6378
81