Mathematics
Undergraduate
(4)(5)の途中式教えてください！
解答は、(4)→2/3,(5)→0です。
373 次の式を簡単にせよ。
0 1ogs4Tlog。9 ⑫) 1ogj。25十log ,。4
og。276 log。73
(3) 1og。18一log。2
短 2og。/5ーまoe。3Tig
Answers
No answer yet
Were you able to resolve your confusion?
Users viewing this question
are also looking at these questions 😉
