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English Senior High

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Review Reading 4: Selecting the Olympic Sports Fluency Practice し Time yourself as you read through the passage. Write your time in the space at the bottom of the page. Then answer the questions on the next page. Selecting the Olympig Spos During each Summer Olympic Games, 28 different sports are played. The kinds of sports played at the Olympics don't change very often, and the process for changing them is long and difficult. So it came as a big surprise in 2005 when the International Olympic Committee (IOC) announced that it wanted to add new sports to the Summer Olympic Games. At that time, the list of sports hadn't changed in 70 years. 5 At a meeting in Singapore in 2005, the lOC voted on each of the 28 events from the 2004 10 Olympic Games in Athens, Greece. They wanted to choose which sports would be played at the 2016 games. There are many reasons why some sports make the list while others don't, but it's important that these sports are popular around the world, and played in many different countries. The committee decided that baseball and softball would be replaced. Their new options included roller skating, rugby, golf, squash, and karate. To be included in the Olympics, a sport must receive votes from at least two-thirds of the committee. The IOC had to meet more than once to come to a conclusion. Finally, in 2009, the results were announced: rugby and golf were the newest Olympic sports. 15 Both rugby and golf have been Olympic sports before. Golf was part of the 1904 games over a century ago, and rugby was last played in the 1924 games. Now, both sports will rejoin 25 the Olympics for the 2016 Summer Gamesin Rio de |20 Janeiro, Brazil. Athletes from both sports are excited. New Zealand rugby star Jonah Lomu said, "(t's) just fantastic for the game." Golf superstar Jack Nicklaus feels just as strongly. He says that "now people of all walks of life1 will be inspired to play the game of golf, and play for sports' highest recognition. For all sports, that has always been a gold medal." 1 People from all walks of life are people from different backgrounds, cultures, or positions in society. 335 words Time taken

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English Senior High

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1 ()に入れるのに最も適切なものを選び、番号をマークしなさい。(各1点) 1 The term of the contract ( ) for three years. Orun 2 is running (3) runs の have run 2 You( D had better not ② had not better ③ not had better ④ had better not to ) swim in this river. It's dangerous. 3I recommended that she ( ) the professor. D had seen saw 3 should see ④ would see 4 He looks quite young. He ( 0 cannot 2 may ) be over 50. 3 ought to ④ must 5“Is Bill still using your car?" "Yes, I wonder when he ( ) it.” fcob dw ta の has returned ② returned ③ returns 0w(4) will return 6 It has been hard to concentrate on my studies lately because a road ( )in front of my house. O builds 2 has built ③ is being built ④ is building 7 The book I am reading is so exciting! I will lend it to you as soon as I ( )it. 0 will have finished 2 will finish ③ have finished am going to finish 8 The mountain is ( ) snow. 0 covering by ② covering with③ covered by ④ covered with 9 We've just missed the train. Dshould We( ) left our office a little earlier. 2should not 3should have のshould not have 10 Be sure to turn off the lights when you ) the room. の leave 2 will leave 3 left ④ leaving 11 Half of the students in this class ( ) glasses. ② are wearing ③ is wearing 0 put on 4) wear 12 He sold the TV set which he ( )only a few months before. ① has watched ② has used from ③ had bought ④ got in 1

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Physics Senior High

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4月 30 日 J 版 15 (i)物体Aが時刻 30s に連度8.0m/s で原点を 通過後、x軸上を一定の加速度-2.0m/sで進む。 (a)=0~6,0s の運動をp-4 図に表せ。 (b)t=0~6.0s での移動距離(m), および =6,0s での変位 x[m] を求めよ。 (a) 時刻 での連度e は、 o=8,0m/s. a=-2,0m/" より ぃ=80-2.0f となる (下四)。 (m/s)t 等加速度直線運動の -t 図から変位を求める 日速度 D →岡回 -t 図の面構ー変位 x この部分の面 =6.0sのとき =8.0- 2.0×6,0=-4.0m/s + at ar 1. 8.0 この部分の面横= tu の=×8.0×4.0=16m 6.0 4.0 a) 0 D- (b) p-t 図の①+ ④の面積が移動距離!を、 の-のの面積が変位x を表すので O X= of + -4.0 の=合×4.0×2.0-4.0m 2変位の式 a<0 のとき を一定の加速度-2.0m/s" で運動する。時 刻=Os に原点を速度8.0m/s で通過した。 次の問いに答えよ。 物体Aがr軸上 1= 16+4.0= 20m *= 16-4.0= 12m 例題 時刻 t=D3.0s でのAの変位×[m] を求 めよ。 (3)物体Aが時刻 3Os に速度 12m/s で原点を通 過後、x軸上を一定の加速度-2.0m/s' で進む。 (a)t=0~8.0s のAの運動を ひt図に表せ。 解 a=-2,0m/s° =3.0s [m/s) =0s = 8.0m/s 変位 0 a= -2.0m/s。, v0=8.0m/s, t=3.0s よ り i (a) *= Dod + af=8.0×3.0+×(-2.0) ×3.0° = 15m (b) v-t 図を用いて=0~8.0s での移動距離1 [m),および t=8.0s での変位x(m] を求めよ。 変位と移動距離の違いに注意 変位xノ 移動距離 1)時刻t=2.0s でのAの変位x[m] を求めよ。 8.0X204×(-20x 2,0° 16+(-40)-ヤ (2m 1: (4)物体Aが時刻 %3D0S に速度8.0m/s で原点を通 過後、x軸上を一定の加速度-4.0m/s° で進む。 (a) t=0~5.0s のAの運動をひ-t 図に表せ。 p(m/s) ニ 時刻t=4.0s でのAの変位x [m]を求めよ。る 8.X40+台×(シx4,0° 0 ニ 32t(-10)= 16 16m 静刻t= 10.0s でのAの変位x[mを求めよ。 - 8,0X/a04x(-0)Xlo. (b) pt図を用いて t%3D0~5.0s での移動距離! およびt=5.0s での変位x(m] を求めよ。

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