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英語 高校生

英語長文ハイパートレーニング③に載っていた長文です。右ページ3行目の文の文構造がよく分からないので教えて頂きたいです。特にas was to beの意味が分からないです🙇🏻

UNIT 8 出題データ 10 ●ワード数: 422 words ■難易度 : 難 解答と解説:本冊 p. 112~127 次の英文を読み, 後の問いに答えなさい。 school. As was to be expected in a country far less calm than the world imagines, Zurich's proposal has produced an uproar. În educational circles/it is argued that French will lose its strong position in German- speaking Switzerland (eight years of school French before entering the university at 19), and that/ this could endanger the political unity of Switzerland. /French-Swiss politicians are furious. Protests about the possible damage to the teaching of German in French-speaking Switzerland are more puzzling, because the German taught there is High German, the dialect of South and Central Germany. But in daily life, (3) as distinct from formal writing, Swiss-Germans speak one or the other of their very different dialects. Hence the liking for English as a "national link language."ids Dual The 26 ministers have hurriedly set up a committee, (naturally headed by a professor of French) to (4) work out a policy by the middle world with a better command of English. 運用能力 of this year. (5) It may well come up with wise recommendations At the moment, English is officially taught for only one or two years before the school-leaving age of 16. Changing such practices is enabling every canton to choose its own solution.) The Swiss are not never easy in Switzerland. There is no national ministry of education. 40 easily *regimented, drilgne vous von *[注] canton (スイスの) 州, 県 ■設問■ 1. Which one of the following best describes the main point of this article? Indicate your choice on your mark sheet. 目標解答時間 : 25分) Switzerland has a language problem. The trouble is not a shortage of tongues, for the Swiss have four of their own. Some 65% speak one 30 variety or another of Swiss-German, /18% speak French/ 10% speak Italian and nearly 1% speak one of the four Romansh dialects (u used in 5 some of the valleys in the *canton of the Grisons. There are also the languages of the many immigrant workers. The problem is that many て 35 Swiss parents, (1) not to mention businessmen who want to talk to M colleagues abroad, would like more Swiss children to (2) go out into the 同僚 The 26 cantons are independent in cultural and educational affairs. So 26 education ministers have to 独立している meet (in order to decide on 15 recommendations which, to become law, then have to get through 26 parliaments. That is why it took Switzerland more than 20 years to introduce teaching in a second national language (German or French) at the age of 11 instead of 14. This time, however, one canton, deciding it had waited long enough) 20 has broken the deadlock./Zurich, the most populous of the cantons, and the heart of the Swiss banking world, plans to make English a required 行きづまり 銀行薬 UNIT 8 subject at an early age, /maybe even from the first year of primary 小学校 regiment 統制する English is important because it has become the international language. Language policy is a serious political issue in Switzerland. 3 Countries like Switzerland need to teach many foreign languages. It is impossible to deny the increasing significance of English. 5 Switzerland needs English to serve as a "national link language." 27

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数学 高校生

この問題で、延長線を使わなくてはいけない理由はなんですか?仮定で、△ABCの辺BCをAB:ACに内分するって言っているので、∠Aの二等分線⇒BP:PC=AB:ACが成り立つからAPは∠Aの二等分線である、という証明ではダメなのですか?

000 Sluts ABCの辺BC を AB : AC に内分する点をPとする。このとき, APは∠A の二等分線であることを証明せよ。 例題 72 角の二等分線の定理の逆 問題文の内容を式で表すと,次のようになる。 指針 p.448 基本事項 2 定理1(内角の二等分線の定理) の逆である。 BP: PC=AB: AC ⇒ APは∠Aの二等分線 ( ∠BAP=∠CAP) △ABCにおいて、辺BAの延長上に点D ACAD となるようにとる。 つまり, 線分の比に関する条件から, 角が等しいことを示すことになるが, 線分の比を 扱うときには,平行線を利用するとよい。 ∠Aの二等分線BP : PC=AB AC の証明 (p.448 解説)にならい, まず辺 BAのAを越える延長上に, AC=AD となるような点Dをとることから始める。 別解 ∠Aの二等分線と辺BCの交点をDとして, 2点P, D が一致することを示す。 なお、このような証明方法を同一法または一致法という。 p.453 における三角形の重心の証明でも同一法を用いている。 ゆえに SISAKOLA Camar BP:PC=AB:ACのとき, BP : PC=BA : AD から平行線と線分の比の性質 AP//DCを三角形の重心と の逆 ∠BAP=∠ADC ∠PAC=∠ACD ACAD から ∠ADC=∠ACD よって ∠BAP=∠PAC すなわち, APは∠Aの二等分線である。 別解 辺BC上の点Pが BP: PC=AB:AC B P AB:AC=BD:DC BP:PC=BD:DC DI を満たしているとする。 ∠Aの二等分線と辺BCの交点をDとすると, 内角の 二等分線の定理により TOP p.448 基本事項2 ② あ CHURCO AS IMAG ROCLAAS TÄ したがって, APは∠Aの二等分線である。 HOA B ONOTRE 平行線の同位角、錯角は それぞれ等しい。 MAS △ACD は二等辺三角形。 ①②から 6. FADLOWE よって,PとDは辺BCを同じ比に内分するから一致す 同一法 る。 DP C 451 GROMAE CÓRKA 704 が成り立つ。下の練 3章 3 1 三角形の辺の比、五心

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