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英語 高校生

(21)の答えが3になるのがなんでか少し分からないです…わかる方いますか??

(21) (22) (23) Any Change? Long ago, humans did not use money. Because they often could not produce everything that they needed, they traded some of their goods for goods made by others. Gradually, the goods that they exchanged were replaced by cash. For hundreds of years, metal coins and paper bills that can be exchanged for goods and services have been produced. Cash is convenient for many people because it is easy to carry. At the same time, though, it ( 21 ). Another disadvantage is that criminals have been able to produce fake coins and bills. In the middle of the 20th century, plastic credit cards were introduced. They had security features to prevent them from being used by anyone except their owners. At first, their use was limited to wealthy people. Over time, however, they became ( 22 ). In the last few years, apps for smartphones that can be used in the same way as credit cards have also become popular. Because of this, some people are suggesting that we may soon see the end of cash. Supporters of a "cashless" society in which all payments are made electronically argue that it would have several benefits. For example, people would not have to worry about keeping their wallets safe. However, some people are concerned that they might be unable to pay for the things they need because of a software error or a broken smartphone. Moreover, some people do not have bank accounts or credit cards, so their only option is to use coins and bills. ( 23 ), it seems as though societies will continue to use cash. 1 can be lost or stolen can be recycled 1 thinner and lighter 3 harder to use 1 For now 2 Until then 2 4 2 4 3 is used for shopping online is understood by almost everyone more colorful and exciting more widely available With luck 4 By contrast

解決済み 回答数: 1
数学 高校生

72.1 原点Oについての文章は必要ですか? また必要ならなぜ必要なのでしょうか?

[0] 基本例題 12 座標を利用した証明 (1) 食 (1) △ABCの重心をGとする。 このとき, 等式 ABCT)ALLED AB'+BC2 + CA'=3(GA²+GB2 + GC2) が成り立つことを証明せよ。 9 $ (2) △ABCにおいて, 辺BC を 1:2に内分する点をDとする。 このとき, 等式 2AB'+AC2=3AD' +6BD' が成り立つことを証明せよ。 TOLOUR MAT 指針 座標を利用すると, 図形の性質が簡単に証明できる場合がある。 そのとき 0 31 けで AB この座標軸をどこにとるか、 与えられた図形を座標を用いてどう表すか がポイントになる。そこで後の計算がらくになるようにするため,問題の点がなるべく 多く座標軸上にくるように 0が多いようにとる。 (1) は A(3a, 36), B(-c, 0), C(c, 0) とすると, 重心の性質からG(a,b) (2) l A(a, b), B(-c, 0), C(2c, 0) CHART 座標の工夫 1 0 を多く ② 対称に点をとる Let 解答 (1) 直線BC をx軸に, 辺BCの垂直二等分線をy軸にとると,| 線分BCの中点は原点0になる。 A (3a, 36),B(-c, 0), C(c, 0) とすると, Gは重心であるからG(α, b) と表される。 よって AB2+BC2 + CA 2 (1) +8+-- =(-c-3a)² +962+4c²+(3a-c)2 +962 ① の場=6a²+662+2c2 ...... 0212 =3(6a²+6b²+2c²) HOMEB 平行四辺 GA2+ GB2+GC 2 (1=(3a-a)²+(36−b)²+(-c-a)²+b²+(c-a)² + b² ② ① ② から AB2+BC2+CA²=3(GA+GB2+GC2) (②2) 直線BCをx軸に点D を通り直線BC に垂直な直線を y軸にとると,点Dは原点になり, A (a,b), B(-c, 0),( (20) と表すことができる。 24+ (x + (11) M よって 2AB'+AC'=2{(-c-a)+(-6)^}+(2c-a)+(-6) 2 =2(c²+2ca+a²+b²)+4c²−4ca+a²+6² 2)2 2007 =3a²+3b²+6c² 3AD²+6BD²=3(a²+b²)+6c² ①②から 基本 71 ② B (-C,0) 2AB²+AC²=3AD²+6BD² +3,0 0-8 A 基本 85 EA(3a, 36) 0 (G (a,b) (c, 0) x y A(a, b) (E) 4 B12- (-c, 0) OD a(s) 2−)Ɔ (^_{}ª_{{I_DA Mɛ (1) 3DSMATRROS:8,9% 音の点をPとする。このとき,等式 117 (2c, 0) x ET 3章 12 直線上の点、平面上の点

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