Q： 中2理科電流 ． 電流計の使い方についてで、｛ 電球に対して電流計を並列に繋ぐ ｝ ことが注意事項として紹介されていたのですが、その状態を上手くイメージできません ( ᐡ•̥ •̥) 図なり画像なりで教えていただきたいです！

例題126の(2)がまったくわからないので教えてください。

重要 例題 126 三角方程式の解の個数 000 aは定数とする。 0≦0<2 のとき, 方程式 in-sin0=aについて (1)この方程式が解をもつためのαのとりうる値の範囲を求めよ。 (2)この方程式の解の個数をαの値によって場合分けして求めよ。 CHART & SOLUTION =y 基 方程式f(0)αの解 2つのグラフ y=f(0),y=aの共有点 (0≦02) の解の個数 k=±1 で場合分け ! ① の個数は=±1 のとき1個; -1<k<1 のとき2個; k< -1, 1<k のとき 0 個 2角 む 2 三角 答 (1) sin²0-sin0=a ①とする sinQ CO

こういう英語の問題はどうやって勉強すればいいですか？

A. 次の問い (問1~問3)において、下線部の発音がほかの三つの場合と異なるものを, それ それ①~④の中から一つずつ選びなさい。 問1 ① calculate false ③ radical strategy B2 charge ② merchant scholar watch 2 問3 college 2 joke ③ mostly sole 3 B. 次の問い(4,5)において、第一アクセント(強勢)の位置がほかの二つの場合と異な るものを、それぞれ①~④の中から一つずつ選びなさい。 問4 ① al-ter 2 bor-der 問5 a-greement ③loy-al ①pa-trol 4 con-di-tion min-is-ter + re-spec-tive 5

線を引いたところの訳し方を丁寧に教えて頂きたいです🙇‍♀️

L American poet Ralph Waldo Emerson once said, "Every artist was first an amateur." He likely never thought those words would apply to machines. Yet artificial intelligence (AI) has demonstrated a growing talent for creativity, whether writing a heavy-metal rock album or producing an original portrait that is strikingly similar to a Rembrandt. Applying AI to the art world might seem unoriginal; there are, of course, plenty of humans delivering awe-inspiring work. Supporters say, however, the real beauty of training AI to be creative does not lie in the end product-but rather in the technology's potential to expand on its own machine-learning education, and to solve problems by thinking in different ways far faster and better than humans can. For example, creative problem-solving AI could someday make snap decisions that save the lives of the passengers in a self-driving car if its sensors fail. AI with a creative component will be essential in developing highly automated systems that can respond appropriately to human life, says Mark Riedl, an associate professor at Georgia Institute of Technology's School of Interactive Computing. "The fact is, we do lots of little bits of creativity every single day; lots of problem-solving goes on," Riedl says. "If my son gets a toy stuck under the couch, I have to devise a tool from a hanger to get it out." Riedl points out human creativity is also important in human social interactions, even telling a well-timed joke or recognizing a pun. Computers struggle with such subtleties. An incomplete understanding of how humans construct metaphors, for example, was all it took for an experiment in Al-generated literature to compose a new Harry Potter chapter filled with nonsensical sentences such as, "The floor of the castle seemed like a large pile

2と3が分かりません 2の3と4はどう違いますか？ 3はin on の使い分けがよく分かりません

grom Bimbute tot al webwi (1) 1 Choose the most appropriate choice to complete each sentence. si wall into 1 jar viniemes blow C ) ten years since the two companies merged. ①has been 2 has passed 3 is passed 4 go (1) It ( (2)( 3 What do you think is ) the biggest challenge in high school education today? Do you think that Do you think what it is What do you think it is A: What time does the library close? B: It closes at 9 p.m. Monday to Friday and 6 p.m. ( 1 at 2 by 3 in 4 on (4) The elderly woman, ( The elderly her. (5) If I ( of u bemut ) Saturdays. (05) ) had known Tom well, said that he was very kind to what whom ③which ④whood stamco bosolmald 1 can ) to win a lot of money, the first thing I would do is buy a new car. 2 could 3 has 4 were

絶対値外したらなんでiが消えるのか教えて欲しいです。

148 基本 例題 80 2点間の距離 00000 3点A(5+4i),B(3-2i), C(1+2i) について,次の点を表す複素数を求めよ (1) 2点A,B から等距離にある虚軸上の点P (2)3点A,B,Cから等距離にある点 Q CHART & SOLUTION 複素数平面上の2点A(α), B(β) 間の距離 AB=|β-α| |β-a|=|p+gil=√2+q2 β-a=p+gi (p, gは実数) のとき (1) 虚軸上の点をP(ki) (k は実数) とおき AP=BP (2) Q(a+bi) (a, b は実数) とおき AQ=BQ=CQ 解答 (1) P(ki) (k は実数) とすると AP2=|ki-(5+4i)=(-5)+(k-4)i =(-5)²+(k−4)²=k²-8k+41 BP2=|ki-(3-2i)|=|(-3)+(k+2)i =(-3)2+(k+2)=k'+4k+13 p.141 基本事項 「kは実数」の断りは AP≧0, BP≧0 のとき 基本 例題 81 ||=1 かつ | (1) zz CHART & S 複素数の絶対値 (1)zz= |2|2 (3)(1),(2)の結 別解 解答 z=a+ (1)zz=z2 (2)|z+il=√ よって すなわち 展開すると zz=1を代 ya • A P 0 X AP = BP より AP2=BP2 であるから k2-8k+41=k2+4k+13 なんでできえるの? ・B これを解いて k= 7 したがって、点Pを表す複素数は i 3 実 (2) Q(a+bi)(a, b は実数) とすると AQ2=l(a+bi)-(5+4i)|= l(a-5)+(6-4)i 「a, b は実数」の断りは 重要。 (2) 両辺に =(a-5)2+(6-4) 2 YA 73 AP=BPAP'=B よって (3) z=0 で BQ²=l(a+bi)-(3-2)=(a-3)+(6+2)i =(a-3)2+(b+2 ) 2 CQ=l(a+bi)-(1+2i)|= l(a-1)+(b-2)i =(a−1)²+(6-2)² AQ=BQ より AQ'=BQ2 であるから 整理すると (a-5)2+(6-4)2=(a-3)2+(6+2) a+36=7 BQ=CQ より BQ=CQ2 であるから (a-3)2+(b+2)2=(a-1)2+(6-2)2 整理すると a-26=2 ...... ② ①,②を解くと a=4,b=1 したがって,点Q を表す複素数は 4+i PRACTICE 802 Q 0 B ABC は∠Cが直 inf. の直角二等辺三角形で あるので、求める点は ABの中点である。 3点A(-2-2i), B(5-3ź), C(2+6ź) について,次の点を表す複素数を求めよ。 (1) 2点A, B から等距離にある虚軸上の点P (2)3点A,B,Cから等距離にある点 Q よって ゆえに したがっ 別解 2=C z=a-b (2)より, また b= したがっ PRACTI ||=5カ (1) zz

下から15行目のthrow whichのthrow とはなんですか？

y II Day 12 15 5 Negro Leagues Baseball was a collection of major and minor-league baseball leagues that were the first to showcase black team sports on intertwined with the African American and American experience not only a national scale. Launched in 1895, the leagues, as with jazz, became as a cultural element, but as a lucrative business endeavor. team The leagues were not under central management, and schedules and composition League, were changeable from season to season. Appearance and disappearance of leagues was common: the National Colored Baseball for instance, collapsed after only two weeks of operations. Latins, especially Cubans, were also a significant presence on teams. In these ways, the Negro Leagues were quite similar to their white counterparts which would eventually consolidate into Major League Baseball. Blacks near the beginning of the 20th century had only a fraction of whites' purchasing power, so the emergence of the Negro Leagues might have seemed unlikely. However, the Negro Leagues had two main draws that accounted for its business success. The first was a deep reserve of athletic talent. After blacks were formally excluded from white leagues in the 1880s, the Negro Leagues were the sole organization through which black players could work professionally. The quality of Negro Leagues 20 players was high, and substantiated through exhibition matches between Negro Leagues and Major League teams: over the years, both had their fair share of wins and losses in these matches. Another reason for the success of the Negro Leagues was an increasingly affluent black fan base. Driven by American industrialization, blacks were concentrating in major cities such as New York City, Chicago, and Atlanta. Usually barred by custom-and in the South by law-from attending many white entertainment outlets, blacks turned to Negro Leagues games. As a result of these factors, by the 20th century the Negro Leagues were earning a combined millions of dollars. This profitability ended with the desegregation of Major League Baseball. Black fans began attending Major League games, starving the Negro Leagues of its core revenue source. By 1951, the Negro Leagues had ended, although a succession of black star athletes in the Major League had begun.

(2)この解き方ってありですか？

(1)22=(21=1 (2) (2-7)² = 2-222 + 12 マーラー

数IIの（2）がわかりません。 [と〇の部分がわかりません。

96 重要 例題 57 剰余の定 (1) f(x)=x-ax +6 が (x-1)2で割り切 を温以上の整数とするとき、 x-1 を (x-1)で割ったときの余りを 求めよ。 CHART & SOLUTION 割り算の問題 基本公式 A=BQ+R を利用 1 次数に注目 ② 余りには剰余の定理 [学習院大] 基本 53 (1)(x-1)2で割り切れる⇒f(x)=(x-1)2Q)×(左党 ⇒f(x)がx-1で割り切れ、更にその商がx-1で割り切れる。 (2)次の恒等式を利用する。 ただし, nは自然数とし,°=1,6°=1である。 解答 a-b"= (a-b)(a1+α"-26+α"-362++ab"-2+6"-1) (1) f(x) は x-1で割り切れるからdf(1)=0 よって 1-a+b=0 -aa-1 L ,348 10 1 1 -α+1 ゆえに b=a-1.. ・① したがって f(x)=x-ax+α-1 =(x-1)(x2+x+1-α ) ST-A-AS-8-Sa-11-a+1 g(x)=x2+x+1-α とすると よって 3-a=0 ゆえに g(1)=0 a=3 条件から,g(x)も で割り切れる。 これを 1 に代入して b=2 (2) x-1 を2次式 (x-1)2で割ったときの商をQ(x), 余 りを ax + b とすると,次の等式が成り立つ。-xs- x"-1=(x-1)2Q(x)+ax+b 両辺に x=1 を代入すると 1 割り算の基本公式 A=BQ+R ゆえに x"-1=(x-1)2Q(x)+ax-a 0=a+b よって b=-a =(x-1){(x-1)Q(x)+α} x"-1=(x-1)(x"-1+x"-2++x+1)であるから xn-1+x"-2+……………+x+1=(x-1)Q(x)+α) (x-1)2Q(x)+α 1=x であるか b=-a=-n) (S-x)=8の項数はxから 両辺に x=1 を代入すると 1+1+....+1+1= a よって a=n ゆえに したがって、求める余りは nx-n PRACTICE 570 での

数II複素数の問題です。 下の鉛筆でかいてあるとおりD>0では？

82 SSURA 49 2次方程式の解の存在範囲 (2) ※実習い方の3次方程式ピー(a-1)x+a+6=0が次のような解をもつよう αの値の範囲をそれぞれ求めよ。 (1) 2つの解がともに2以上である (2) 1つの解は2より大きく, 他の解は2より小さい。 CHART & SOLUTION 実数解 α, β と実数の大小 α-k, β-kの符号から考える NO.76 基本事項 5 基本48 (1) 2以上とは2を含むから, 等号が入ることに注意する。 a≥2, B≥2 (a-2)+(B-2)≥0, (a-2)(B-2)≥0 (2)α <2<β または β<2<a⇔ (-2)(β-2)<0 解答 5) (1-1)=(8- x2-(a-1)x+a+6=0 の2つの解をα, βとし, 判別式を Dとすると D={-(a-1)}-4(a+6)=α²-6α-23 解と係数の関係により a+β=a-1, aβ=a+6 (1) α≧2,β≧2 であるための条件は,次の① ② ③ が同 時に成り立つことである。 2つの色のDEO ため金×(μ-2)+(3-2)≧0 D=0で?(α-2) (B-2)≧0 で ② ****** (3) ! inf. 2次関数 f(x)=x-a-1)x+a+6 のグラフを利用すると (1)D≧0, (軸の位置) ≧ 2, (2)0 D a-1 x= 2 重要 4x 定 Q