例8) 25℃で次の水溶液の水素イオン濃度とpHを求めよ.
(1) 0.010 mol/Lo +
(1.0)
Hcl
[H²] = 1 x 0.010 × 1.0 = 0,01
=
102
<-2
A₁ [H²] = 1,0 x 10² mol/L
PH = 2
(2) 0.050mol/Lの酢酸水溶液(電~0.020) CH3COOH TO
-2
[H+] = 1 x 0.050 x 0.020 = 0,01 = 10
[H+] = 1.0 x 15² mol/L
_PH=2
0.05
010
GP 00,01²