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酸素Oを-2、カリウムKを+1として、全体が0になるようにCrの酸化数を求めます。
K2 Cr2 O7
↓
(+1)×2 + Cr×2 + (-2)×7 = 0
2 + 2Cr -14 =0
2Cr = 12
Cr = 6
6価だとおもいます！
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