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参考・概略です

(1)    x=(1-√3i)/2

    2x=1-√3i

   2x-1=-√3i

 (2x-1)²=(-√3i)²

4x²-4x+1=-3

4x²-4x+4=0

 x²-x+1=0

(2) x³+x²+3x+2=(x²-x+1)(x+2)+4x

 【(1)より】  =4x

 【xの値を代入】=4×{(1-√3i)/2}

         =2-2√3i

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x^2-x+1を作りましょう。
おまけとして(1)の別解もつけておきました。

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