Physics
Senior High
Resolved
この計算の途中課程を教えて頂きたいです🙇🏼♀️
求める距離xは
2/3
3 Vg
2
h
x=(620万) (
2/3
3 Vg
h
2gh
2
6球に就4+2,6
-h →ツ~ナ
3
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ありがとうございます🙇🏼♀️