Mathematics
Senior High
解き方、ヒントを教えて欲しいです
356 次の不定積分を求めよ。
Jsina
sin xcosxcos2.xdx
」(sing+co)a
dx
( Jcos3rsin5zdz
(4)* | sin 2x sin4xdx
1S
6 [an'号co0号
sin?
TRIAL A
365 次の定積分を求めよ。
(* S"
(2) dx
-dx
4
。2
dx
* e+1 dy
1-y
2
X
( SSin0 do0
6"f"。
cos tdt
き dx
cos?x
dx
366 次の定積分を求めよ。
(1)(2x°+6x?+2x-3)dx
(2) (x-3x?- 2x+4)dx
4x+1
-dx
x+1\2
1 x
dx
x
3)
0
x+1
-dx
*Piー
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