Mathematics
Junior High
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(3)と(4)と(5)の計算の答えが間違っているんですけど、どこが違うのかが分からないです。
途中式お願いします🙇♀️
41x²-14
(3) (4a-b)²-(a+b)(a-2b)
=/ba² - Sab + b ² + ( a ² + b +26²)
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= 15a²-8ab 3 b ² + b
2 次の計算をし
(1) (4a-1)²-3
= 16a² + 8 a
(4) (a+1)(a-1)-(a-1)²
= 17a² & 1
= a ² + 1 + (=a² + 2a4²-1)
= 2 α
(5) (4x-1)(4x+5)-(2x+1)²
2
= 72²² +12
= 16x² + 16x + 4 + (-4x²4-4x +-/) (2) (x+6) ²—
=12x²+12x+3
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