Mathematics
Senior High
この解き方は間違っていますか？
答えは1/3になります
lim (1:2+23+…+n(n+1))
3
n→∞ n
31412
初項2項n(n+1) 項数2n+2
Sn = = = x(2n+2) x √{2+ n(n+1)]
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