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sinxcosxのn次導関数について、
答えが2^(n-1)･sin(2x+nπ/2) となるそうですが途中式を教えて欲しいです。
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sinxcosxのn次導関数について、
答えが2^(n-1)･sin(2x+nπ/2) となるそうですが途中式を教えて欲しいです。
Users viewing this question
are also looking at these questions 😉
@ありがとうございます