Mathematics
Undergraduate
Solved
sinxcosxのn次導関数について、
答えが2^(n-1)･sin(2x+nπ/2) となるそうですが途中式を教えて欲しいです。
Answers
Were you able to resolve your confusion?
Users viewing this question
are also looking at these questions 😉
sinxcosxのn次導関数について、
答えが2^(n-1)･sin(2x+nπ/2) となるそうですが途中式を教えて欲しいです。
Users viewing this question
are also looking at these questions 😉
@ありがとうございます