Mathematics
Senior High
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最後、27になってるところ、何回やっても-9になるんですがどこが間違ってますか?🙇‍♂️

S=AADF+ADBE {(6-x)²+x²} 4- (0) =3(x²-6x+18) =3(x-3)²+273)-1. ① において.Sはx=3で最小値 27 3 = 2²2 JEHO
3 (x² - 6x + 18) = 3 -{(x-3) ²=93 +18 = 3 (x-3)² + 18-27 =3(x-3)-9

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