Mathematics
Senior High
Solved
最後、27になってるところ、何回やっても-9になるんですがどこが間違ってますか?🙇♂️
S=AADF+ADBE
{(6-x)²+x²}
4-
(0) =3(x²-6x+18)
=3(x-3)²+273)-1.
① において.Sはx=3で最小値 27
3
= 2²2
JEHO
3 (x² - 6x + 18)
= 3 -{(x-3) ²=93 +18
= 3 (x-3)² + 18-27
=3(x-3)-9
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なるほど!ありがとうございます!