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[k=1,n]Σaₖ=Sₙとします.
条件から、
~~~~~~~~~~
S₂₀=(1/2)・20(2a₁+19d)=400
S₃₀=(1/2)・30(2a₁+29d)=900
~~~~~~~~~~

~~~~~~~~~~
2a₁+19d=40
2a₁+29d=60
~~~~~~~~~~
2式引いて、
10d=20⇔d=2
a₁=(40-19d)/2=1

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